factoriser: (a−4)² −(a−6)² (1−6/7 )²−(−10−6/7 )² merci d'avance
Mathématiques
teamabssonwave
Question
factoriser:
(a−4)² −(a−6)²
(1−6/7 )²−(−10−6/7 )²
merci d'avance
(a−4)² −(a−6)²
(1−6/7 )²−(−10−6/7 )²
merci d'avance
1 Réponse
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1. Réponse inequation
Bonsoir
Factoriser:
(a−4)² −(a−6)²= (a-4-a+6)(a-4+a-6)= 2(2a-10)= 4(a-5)
(1−6/7 )²−(−10−6/7 )²= (1-6/7 -(-10-6/7 )(1-6/7 +(-10-6/7 )
= (1-6/7 +10+6/7 )(1-6/7 -10-6/7 )
= [(1*7-6+7*10+6)/7 ] [ (1*7-6-7*10-6)/7 ]
= (11)(-75/7)= -825/7