( 7x+1)2-(3x+4)2=0 svp!!!! (6x-1)2-(2x+1)2=0
Mathématiques
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Question
(
7x+1)2-(3x+4)2=0 svp!!!!
(6x-1)2-(2x+1)2=0
2 Réponse
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1. Réponse winner123
bonjour
7x+1)2-(3x+4)2=0
14x +2 - 6x + 8 = 0
8x +10 = 0
8x = -10
x = -10/8
x = - 5/4
(6x-1)2-(2x+1)2=0
12x -2 -4x - 2 = 0
8x - 4 = 0
8x = 4
x = 4/8
x = 1/2 -
2. Réponse geekkhalil
Salut :)
(7x+1)2-(3x+4)2=0
2 (4 x-3) = 0
8 x-6 = 0
(6x-1)2-(2x+1)2=0
4 (2 x-1) = 0
8 x-4 = 0