Comment factoriser (2*x-3)*(2*x-3)-4*(x+2)*(9-6*x) ?
Mathématiques
raind
Question
Comment factoriser (2*x-3)*(2*x-3)-4*(x+2)*(9-6*x) ?
2 Réponse
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1. Réponse winner123
Bonjour
(2x-3)(2x-3)-4(x+2)(9-6x)
(2x-3) - (4x+8) -3(-3 + 2x)
(2x-3) - (4x+8 -3)
(2x-3) - (4x +5) -
2. Réponse Anonyme
Bonjour,
Factoriser:
[tex] (2x-3)(2x-3)-4(x+2)(9-6x) [/tex]
[tex]=(2x-3) - (4x+8) -3(-3 + 2x)[/tex]
[tex]=(2x-3) - (4x+8 -3)[/tex]
[tex]=(2x-3) - (4x +5)[/tex]
Bonne continuation! =)