Résoudre les équations suivantes : 3 ( 2x – 1 ) = 2 - ( x – 3 ) 5 – 2 ( x + 3 ) = 3 – x 8 ( x – 2 ) = 4 ( 2x – 4 ) – 3x
Mathématiques
elisalala
Question
Résoudre les équations suivantes :
3 ( 2x – 1 ) = 2 - ( x – 3 )
5 – 2 ( x + 3 ) = 3 – x
8 ( x – 2 ) = 4 ( 2x – 4 ) – 3x
3 ( 2x – 1 ) = 2 - ( x – 3 )
5 – 2 ( x + 3 ) = 3 – x
8 ( x – 2 ) = 4 ( 2x – 4 ) – 3x
2 Réponse
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1. Réponse Margoow2
3 ( 2x – 1 ) = 2 - ( x – 3 )
6x - 3 = 2 - x + 3
6x + x = 2 + 3 + 3
7x = 8
x= 8/7
5 – 2 ( x + 3 ) = 3 – x
5- 2x - 6 = 3 - x
- 2x + x = 3 - 5 + 6
- x = 4
x = - 4
8 ( x – 2 ) = 4 ( 2x – 4 ) – 3x
8x - 16 = 8x - 16 - 3x
8x - 8x + 3x = - 16 +16
3x = 0
x = 0 -
2. Réponse winner123
Bonjour
3 ( 2x – 1 ) = 2 - ( x – 3 )
6x - 3 = 2 - x +3
6x +x = 2 +3 +3
7x = 8
x = 8/7
5 – 2 ( x + 3 ) = 3 – x
5 - 2x - 6 = 3 -x
-2x +x = -5 +6 +3
-x = 4
x = -4
8 ( x – 2 ) = 4 ( 2x – 4 ) – 3x
8x - 16 = 8x -16 -3x
8x -8x +3x = -16+16
3x = 0
x = 0